By Margaret L. Lial, Stanley A. Salzman, Diana L. Hestwood
The 9th version of uncomplicated university arithmetic maintains our ongoing dedication to pro-
vide the absolute best textual content and supplementations package deal that may support teachers train and
students be triumphant. therefore, we've got addressed the various wishes of today’s scholars by
creating a tightly coordinated textual content and expertise package deal that incorporates built-in activi-
ties to assist scholars enhance their research abilities, an enticing layout, up to date applications
and graphs, important gains, and cautious motives of ideas. We’ve additionally multiplied the
supplements and research aids. We’ve remodeled the video sequence right into a entire Lial Video
Library with elevated video insurance and new, more straightforward navigation. And we’ve extra the
new Lial MyWorkBook. we now have additionally replied to the feedback of clients and reviewers
and have further many new examples and routines in accordance with their feedback.
The application is designed to aid scholars be successful in a developmental mathematics
program. It presents the required assessment and assurance of entire numbers, fractions, decimals,
ratio and percentage, percentage, and size, in addition to an advent to algebra and geo-
metry and a preview of records.
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Extra info for Basic College Mathematics (9th Edition)
This shows that the order of numbers in an addition problem does not change the sum. This is known as the property of addition. 107. Add. Recall that parentheses show you what to do first. (a) (65 + 81) + 135 (b) 65 + (81 + 135) 108. Since the answers to Exercise 107(a) and (b) are the same, we see that grouping the numbers differently when adding does not change the sum. This is known as the property of addition. 109. Multiply. (a) 220 * 72 (b) 72 * 220 110. Since the answers to Exercise 109(a) and (b) are the same, we see that the product remains the same when the order of the factors is changed.
6 (b) (d) Being divided 15 =3 5 4 (c) 5ͤ 20 15 ، 5 = 3 20 ، 5 = 4 or or 3 5ͤ 15 20 =4 5 > Work Problem 1 at the Side. Answers 4 24 1. (a) 6ͤ 24 and =4 6 36 (b) 36 , 9 = 4 and =4 9 8 48 (c) 6ͤ 48 and =8 6 7 (d) 6ͤ 42 and 42 , 6 = 7 OBJECTIVE 2 Identify the parts of a division problem. In division, the number being divided is the dividend, the number divided by is the divisor, and the answer is the quotient. 5 Identifying the Parts of a Division Problem EXAMPLE 2 Dividing Whole Numbers Identify the dividend, divisor, and quotient.
Division of any number by 0 cannot be done. To see why, try to find 9,0=? As we have just seen, any division problem can be converted to a multiplication problem so that divisor # quotient ؍dividend. If you convert the preceding problem to its multiplication counterpart, it reads as follows. =9 You already know that 0 times any number must always be 0. ” and you’ll aways get 0 instead of 9. Therefore, the division problem 9 , 0 cannot be done. Mathematicians say it is undefined and have agreed never to divide by 0.